Skip to main content

01 / 05   Refraction

Application note

Refraction and Snell's Law

Predict how an optical interface redirects light and when transmission reaches its critical-angle limit.

An optical interface changes the direction available to transmitted light. This behavior determines how a lens focuses, how a prism redirects a beam, and how a protective window affects an imaging path. The starting point is the refractive index on each side of the interface and the angle at which light arrives.

Measure angles from the normal

The surface normal is perpendicular to the interface at the point where the ray arrives. Both the incident angle θ1\theta_1 and transmitted angle θ2\theta_2 are measured from this normal. Snell’s law connects those angles:

n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1=n_2\sin\theta_2

The dimensionless indices n1n_1 and n2n_2 describe the incident and transmitted media. A higher transmitted index reduces the angle to the normal; a lower index increases it, provided a transmitted ray exists. At normal incidence, the ray continues along the normal even when the index changes.

Incident and transmitted rays are measured from the surface normal, with bending toward or away from it depending on the index change.

View diagram at full size

For n1=1.00n_1=1.00, n2=1.50n_2=1.50, and θ1=40∘\theta_1=40^\circ, the transmitted angle is approximately 25.37∘25.37^\circ. Reversing the propagation direction through the same interface retraces that path. A curved surface applies the same rule locally, but its normal changes with position; this is how a lens redirects different rays toward an image.

Recognize the transmission boundary

When light travels from a higher to a lower index, the transmitted ray approaches the interface as incidence increases. The critical angle is:

θc=sin⁡−1(n2n1),n1>n2\theta_c=\sin^{-1}\left(\frac{n_2}{n_1}\right),\qquad n_1>n_2

At this boundary, the limiting transmitted direction is parallel to the surface. Above it, total internal reflection replaces the propagating transmitted ray. For an index change from 1.50 to 1.00, θc≈41.81∘\theta_c\approx41.81^\circ; incidence at 50∘50^\circ therefore produces total internal reflection. There is no corresponding threshold when entering an equal or higher index.

Below the critical angle a transmitted ray exists; at the boundary it is grazing, and above it the ray is totally internally reflected.

View diagram at full size

Apply the result to an optical path

Use indices specified at the operating wavelength. Refraction predicts direction; it does not by itself determine how much optical power is transmitted or reflected. Surface coatings, polarization, and absorption require additional analysis.

For a window or prism, follow each interface in sequence and use its own local normal. A valid ray at the entrance does not guarantee transmission at the exit. The calculators below separate transmitted direction from the critical-angle check, providing a useful first assessment before evaluating a complete optical assembly.

Explore the model

Refraction angle

Calculate the transmitted direction or identify total internal reflection.

Change the example values to update the results and diagram. Use the stated units and sign convention.

Measured from the surface normal; 0° to 90°.

Refracted angle from normal
25.374°

The ray transmits into medium 2; reflected power is not calculated.

Refraction angle: updated diagramIncidence 40 degrees from the normal. The ray transmits into medium 2; reflected power is not calculated.n₁ = 1n₂ = 1.5θ₁ = 40°θ₂ = 25.374° from normal
Input-responsive schematic; not to scale. Scroll horizontally on narrow screens. The numerical results define the distances and angles.
Formula & assumptions

n₁ sin θ₁ = n₂ sin θ₂.

Homogeneous, transparent, isotropic media at a specified wavelength. Angles are measured from the normal. At critical incidence the transmitted direction grazes the surface; 90° incident angle is a separate grazing-incidence limit. Fresnel power, absorption, and evanescent fields are not calculated.

Explore the model

Critical angle

Find the transition from transmission to total internal reflection.

Change the example values to update the results and diagram. Use the stated units and sign convention.

Critical incidence angle
41.8103°

Incidence above this angle gives total internal reflection. At equality the transmitted direction is 90°.

Critical angle: updated diagramIncidence 41.8103 degrees from the normal. Incidence above this angle gives total internal reflection. At equality the transmitted direction is 90°.n₁ = 1.5n₂ = 1θ₁ = 41.8103°θ₂ = 90° from normal
Input-responsive schematic; not to scale. Scroll horizontally on narrow screens. The numerical results define the distances and angles.
Formula & assumptions

θc = asin(n₂/n₁), provided n₁ > n₂.

The ray travels from medium 1 toward medium 2. Total internal reflection requires θ₁ greater than θc. Equality is the grazing transmitted-ray boundary, not the above-critical state.

From estimate to application

Evaluate the interfaces in your optical path.

Material, wavelength, surface angle, and illumination geometry determine which rays reach the next component. Discuss those constraints with Iris Optics.

Discuss your optical path